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With a blend selected, you first need to locate the Start or End blend objects choose either the Show Start or Show End command. Choosing New Start changes the cursor to a targeting cursor, so you can then unlink the Blend effect from one object and target a different one. Doing this creates a new effect each time a different object is targeted. Choosing New End works similarly.

To understand the advantages offered by PVST+ and RSTP, examine Figure 14-13. This example shows two VLANs, numbered 1 and 2. The default behavior with Cisco s switches is that a single root switch is used for all VLANs, based on the switch with the lowest switch ID. In this instance, this is Switch-A. Notice that based on RSTP s calculation, Switch-C disabled its port to Switch-B for both its VLANs. The downside of this design is that of the two connections to the distribution layer, only one is being utilized on the access switch. A better design is shown in Figure 14-14. However, to obtain this kind of topology, you must tune your network, making sure that Switch-A is the root for VLAN 1 and Switch-B is the root for VLAN 2. With this kind of design, you can actually utilize both of your uplink connections on your access layer switch up to the distribution layer switches. In Figure 14-14, VLAN 1 will use the left-hand uplink connection and VLAN 2 the right-hand uplink connection. Based on the design in Figure 14-14, make sure the default gateway for VLAN 1 is Switch-A (assuming it s a layer 3 switch) and for VLAN 2 Switch-B (assuming it s a layer 3 switch). If you don t configure it this way, but have the default gateway associated with Switch-A, VLAN 2 s traffic will have to go from the access layer switch, to Switch-B, and then across the EtherChannel to Switch-A before leaving the subnet. You can learn more about this in Cisco s CCNP Switching course.

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Now we consider the stability of a circuit in the zero-input response case, that is, for a circuit with initial values for currents and voltages but no sources. We can determine zero-input response stability by again looking at the poles of the transfer function H (s). The rst case we consider is when the poles of H (s)are real and negative. In that case the circuit is stable, which indicates that the currents and voltages in the circuit will decay to zero as t . EXAMPLE 14-5 Consider a series RLC circuit with R = 2, C = 1/2, and L = 4. If the initial voltage across the capacitor is v c (0) = 2 and the initial current owing through the capacitor is i c (0) = 0, determine whether the circuit is zero input stable. SOLUTION As usual, KVL around the loop of a series RLC circuit gives LC dv c d 2vc + RC + vc = 0 2 dt dt

Table 21-5.

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